(0.25)^4-x=32

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Solution for (0.25)^4-x=32 equation: 



(0.25)^4-x=32

We move all terms to the left:

(0.25)^4-x-(32)=0

determiningTheFunctionDomain
-x-32+(0.25)^4=0

We add all the numbers together, and all the variables

-1x-31.99609375=0

We move all terms containing x to the left, all other terms to the right

-x=31.99609375

x=31.99609375/-1

x=-31+0.99609375/1

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